Reputation: 6 039
My profile image is a constructive proof that all possible dyadic paritionings of a square cannot be enumerated by an algorithm that recursively partitions by halves horizontally or vertically. Any such solution will contain a strut (a line going all the way across), and the image is strutless. In fact, this image illustrates both of the only two strutless solutions when dividing down to 1/4 (ignoring rotations and reflections). I am the sort of person who finds this interesting.
member since 2017-06-21T03:31:54.327
586 profile views
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