Converting WIF as Base58 string to byte array in bash

0

I want to convert wif as Base58 string to byte array.

Private key to WIF 

printf 800C28FCA386C7A227600B2FE50B7CAE11EC86D3BF1FBE471BE89827E19D72AA1D507A5B8D | xxd -r -p | base58

5HueCGU8rMjxEXxiPuD5BDku4MkFqeZyd4dZ1jvhTVqvbTLvyTJ

Now I want reverse this (WIF to private key), form 5HueCGU8rMjxEXxiPuD5BDku4MkFqeZyd4dZ1jvhTVqvbTLvyTJ to 800C28FCA386C7A227600B2FE50B7CAE11EC86D3BF1FBE471BE89827E19D72AA1D507A5B8D

Im using that library https://github.com/keis/base58 But I can change or better if I can use only bash without extra library

full example https://en.bitcoin.it/wiki/Wallet_import_format

monkeyUser

Posted 2019-01-22T12:46:12.033

Reputation: 245

Are you looking for an alternative tool to decode base58 to hex? – James C. – 2019-01-22T13:29:34.293

no the alternative. with this tool I can't to base58 to hex, or I don't understand How can I that – monkeyUser – 2019-01-22T13:55:11.537

Answers

1

You need to use the decode flag -d:

printf "5HueCGU8rMjxEXxiPuD5BDku4MkFqeZyd4dZ1jvhTVqvbTLvyTJ" | base58 -c -d | xxd -p
800c28fca386c7a227600b2fe50b7cae11ec86d3bf1fbe471be89827e19d
72aa1d

To have xxd output all on one line, give it a large column number -c flag:

$ printf "5HueCGU8rMjxEXxiPuD5BDku4MkFqeZyd4dZ1jvhTVqvbTLvyTJ" | base58 -c -d | xxd -p -c 1000
800c28fca386c7a227600b2fe50b7cae11ec86d3bf1fbe471be89827e19d72aa1d

If you really want the checksum included 507A5B8D (the last 4 bytes), omit the -c flag which denotes checksum encoding:

$ printf "5HueCGU8rMjxEXxiPuD5BDku4MkFqeZyd4dZ1jvhTVqvbTLvyTJ" | base58 -d | xxd -p -c 1000
800c28fca386c7a227600b2fe50b7cae11ec86d3bf1fbe471be89827e19d72aa1d507a5b8d

JBaczuk

Posted 2019-01-22T12:46:12.033

Reputation: 6 172

Asked: 2019-01-22T12:46:12.033

Viewed: 317 times

Active: 2019-01-22T14:19:57.377