Is there any way to recover a bitcoin private key using some parts of the key ?

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I have a bitcoin wallets private key , but it's incomplete like you can say it's 70% of the private key , there is some alphanumeric missing for the middle of the key , is there anyway to recover it using that 70% of it ?

Dion Winbush

Posted 2018-11-11T22:11:12.053

Reputation: 15

What format is the private key in? Please don't share any part of the actual key, just describe the format of the backup/file you do have some part of.chytrik 2018-11-11T22:22:31.027

I wrote that on a paper I have privatekey in WIF format starting with 5.Dion Winbush 2018-11-11T22:25:09.703

1It's a power of 58 possibilities for each character missing (assuming you know the address you are looking for) . So for 4 (58^4) it should be feasible to brute force but for 10 probably not.Mike D 2018-11-11T23:48:24.597

1Depends a lot on exactly what is missing". WIF encoded private keys are a version byte, 32 bytes of data for the private key, and 4 bytes of checksum data. Losing the last few characters is trivially recoverable, losing a couple of characters in the middle is potentially recoverable, losing a substantial portion of the middle of key becomes increasingly more difficult. Work out how many characters exactly you've lost.Anonymous 2018-11-12T00:00:25.590

I think I've lost something about 21 characters from the middle . is it recoverable ?Dion Winbush 2018-11-12T00:50:55.817

Don’t discard it, but unlikely.Anonymous 2018-11-12T03:27:19.010

@chytrik can you recover it ?Dion Winbush 2018-11-12T04:57:48.943

@DionWinbush if you are missing 20+ characters from the middle of the key, as others said it may well be outside the range of brute-forcing. Nonetheless I would keep the information you have: if it is a significant sum, perhaps it is worth trying anyways.chytrik 2018-11-13T21:18:16.390

Answers

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It depends on how much information you are missing.

A Wallet Import Format key is base58 encoded. Thus, each character in the key can be one of 58 characters.

You mention in the comments that you are missing 21 characters. Assuming you know exactly which 21 characters are missing (i.e., you know that the first 21 are missing), you have 21^58, or 4.88336... × 10^76 possibilities. This is outside the range of bruteforcing.

Moreover, if you don't know which 21 characters are missing, you have many, many more possibilities, as you not only need to iterate all 58 possibilities for each characters, but also try all their possible locations within the key.

Unless you are able to find more information, the key cannot be recovered.

Raghav Sood

Posted 2018-11-11T22:11:12.053

Reputation: 10 897

can you give me your email or whatsapp number so I can tell you everything briefly .Dion Winbush 2018-11-12T07:06:54.830

it's 58^21 not 21^58Mike D 2018-11-16T14:06:48.227

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Have you seen the movie "The Imitation Game" ? this reminds me of it because:

if you do have part of it, it 'easier' to get the full message (key) in this case... but exactly by how much?... is it even worth it?

in your case not worth it tho, sorry...

possible? yes, easier? yes, but still not worth it by today's computational standards

Anyways, good luck! and don't throw away anything, you never know....

JosEvora

Posted 2018-11-11T22:11:12.053

Reputation: 1