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Given:
p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
r = 0xd47ce4c025c35ec440bc81d99834a624875161a26bf56ef7fdc0f5d52f843ad1
s1 = 0x44e1ff2dfd8102cf7a47c21d5c9fd5701610d04953c6836596b4fe9dd2f53e3e
s2 = 0x9a5f1c75e461d7ceb1cf3cab9013eb2dc85b6d0da8c3c6e27e3a5a5b3faa5bab
z1 = 0xc0e2d0a89a348de88fda08211c70d1d7e52ccef2eb9459911bf977d587784c6e
z2 = 0x17b0f41c8c337ac1e18c98759e83a8cccbc368dd9d89e5f03cb633c265fd0ddc
How is "P" calculated? Which calculator/script is used to calculate z1*s2, in here ((z1*s2 - z2*s1)/(r*(s1-s2))) and so on????
Thanks so much, I will appreciate your clarification.
I've edited your question to remove the all-caps text. Could you please provide more context? – Murch – 2018-05-12T23:56:10.657
This is the algorithm to determine the the secret key from two signatures with the same nonce. – Pieter Wuille – 2018-05-13T00:03:22.343
And the data is from https://bitcoin.stackexchange.com/questions/35848/recovering-private-key-when-someone-uses-the-same-k-twice-in-ecdsa-signatures which gives Python and Ruby examples.
– dave_thompson_085 – 2018-05-13T15:39:41.667I tired to run the python script from bitcoin.stackexchange.com/questions/35848/… on https://ideone.com/ but I keep getting a syntax error, please where did I go wrong. The example there is not actually working....
– Bill – 2018-05-14T06:58:30.657the example is working fine if you select Python instead of Python 3 – Mike D – 2018-05-14T09:02:45.290