Java: Base58-encode String

I would like to Base58-encode this String:

    56379c7bcd6b41188854e74169f844e8676cf8b8

My current Java code looks like this:

    String test9 = "56379c7bcd6b41188854e74169f844e8676cf8b8";
    byte[] b2 = new BigInteger(test9,16).toByteArray();
    String test8 = Base58.encode(b2);
    System.out.println(test8);

As result I get:

    2CffxtJsCdzJEaHXHjSkvb12p12P

but I should get:

    39YteymR86cG7V3Kijg8Gm2ST1r4nTeM1b

Can someone help me, please?

A.c

Posted 2017-12-29T18:23:43.443

Reputation: 125

Answers

Your output is correct given the input that you used.

However, If you are expecting to get an output address of 39YteymR86cG7V3Kijg8Gm2ST1r4nTeM1b, it looks like your input is incorrect. It's missing the first byte and the last 4 bytes (encoded as hex):

  Your Input: --56379c7bcd6b41188854e74169f844e8676cf8b8--------
Proper Input: 0556379c7bcd6b41188854e74169f844e8676cf8b86e1b34ba

Try this tool for validating your expectations:

Ryan McGeary

Posted 2017-12-29T18:23:43.443

Reputation: 282

Thanks! From where did you know I need do add 05 and 6e1b34ba? – A.c – 2017-12-29T18:51:53.473

I dont know the address before. I only know the String which has then to be base58-encoded to show me the address. – A.c – 2017-12-29T19:03:49.517

@A.c From the site that I linked to in my answer. I reversed your expected output. – Ryan McGeary – 2017-12-29T19:44:32.927