Metcalfe's law for bitcoin price

1

0

Here's an inline link to article

article

    the square function number of users times the average transaction value. 94% of the bitcoin moved over the past four years is explained by that equation.

It does't make sense for me about a mathematical equation of 94% explained bitcoin price in this article.

If I'd like to predict a bitcoin price of following day using this equation, is this as following?

  square function number of users × the average transaction value

       ↓
  square number of unique addresses per day × (trade volume(USD) per day / number of transactions per day)         

     ↓

604,054^2 × (597,502,689 / 271,995) = 801,644,073,110,452

date: 2017/11/14 00:00

Here's an inline link to [reference unique addresses (https://blockchain.info/charts/n-unique-addresses?timespan=30days)

Here's an inline link to [reference trade volume] (https://blockchain.info/ja/charts/trade-volume?timespan=30days)

Here's an inline link to [reference transactions] (https://blockchain.info/ja/charts/n-transactions?timespan=30days)

Answer is very huge number. Could someone explain that concretely where the wrong is?

Thank you

Mikihisa Fukuta

Posted 2017-11-17T03:52:57.160

Reputation: 17

The formatting doesn't seem to have come out as you intended, can you try again? Use the edit button. Here is some info on how to use Markdown and HTML in posts.

Nate Eldredge 2017-11-17T06:25:45.900

thank you I've edited, Could you see my question?Mikihisa Fukuta 2017-11-17T11:04:23.257

No answers