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When trying to redeem a btcc chip I noticed a bad encoded mini private key. One of the character is "l". Anyway has seen this before? I guess these keys are also base58 normally? Thanks
Mini private key with character "l"?
Answers
2
Solved: it appeared to be an "i" but the private key showed it as "l".
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Not too hard to brute-force
static const char* base58 = "123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz";
static void mini ( )
{
char* x = "S6c56bnXQiBjk9mqSY*******NzrRy?";
QByteArray xx ( x );
char* n = xx.data ( );
for ( int i0 ( 0 ); i0 < 58; i0++ ) { n [18] = base58 [i0];
for ( int i1 ( 0 ); i1 < 58; i1++ ) { n [19] = base58 [i1];
for ( int i2 ( 0 ); i2 < 58; i2++ ) { n [20] = base58 [i2];
for ( int i3 ( 0 ); i3 < 58; i3++ ) { n [21] = base58 [i3];
for ( int i4 ( 0 ); i4 < 58; i4++ ) { n [22] = base58 [i4];
for ( int i5 ( 0 ); i5 < 58; i5++ ) { n [23] = base58 [i5];
for ( int i6 ( 0 ); i6 < 58; i6++ ) { n [24] = base58 [i6];
const MyKey32 sha ( MyKey32::sha256 ( xx ) );
if ( sha.constData ( ) [0] == 0 )
{
const QByteArray temp ( xx.constData ( ), 30 );
const MyKey32 priv ( MyKey32::sha256 ( temp ) );
_trace ( QString ( "%1 %2" )
.arg ( priv.toStringWif ( false ) )
.arg ( priv.getAddressHashClassic ( ).toString ( ) ) );
}
}}}}}}}
}
1Might be but I'm not a coder and I don't understand your snippet. Anyway, it's just one character that isn't correct and I wonder how in earth this is possible. I will try to brute force manually :-) – Bart DV – 2016-12-31T13:12:00.667
Have you tried the digit 1, the uppercase i, and the lowercase L? – Pieter Wuille – 2016-12-31T11:15:53.223
Hi Pieter, I tried I and i (but aren't these excluded as it is base58?). – Bart DV – 2016-12-31T11:26:14.840
It's not a 1 neither... – Bart DV – 2016-12-31T11:26:49.073
Please remove the link; it contains enough of your private key to make brute-forcing it worthwile. – maservant – 2016-12-31T12:40:14.680