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Reading the slushpool's manual for the Stratum protocol I found that :
"Default share difficulty is 1 (big-endian target for difficulty 1 is 0x00000000ffff0000000000000000000000000000000000000000000000000000)"
Anyone knows how to generate this 64characters long big-endian representation of the number 1 ? I would appreciate any code in Java.
Thank you
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I'm afraid I don't know Java, but the target is worked out as follows:
target = maximum target / difficulty
Note: The maximum target is
0x00000000FFFF0000000000000000000000000000000000000000000000000000(which in decimal is26959535291011309493156476344723991336010898738574164086137773096960)
Therefore:
target = maximum target / difficulty
target = 26959535291011309493156476344723991336010898738574164086137773096960 / 1
target = 26959535291011309493156476344723991336010898738574164086137773096960
So if you convert that back to hex you get:
0xFFFF0000000000000000000000000000000000000000000000000000
Then you can just pad zeros on the left to make it 64 characters:
0x00000000FFFF0000000000000000000000000000000000000000000000000000
http://learnmeabitcoin.com/manual/guide/difficulty#finding-the-target-using-the-difficulty
Thank you for your information. I read more about the Stratum protocol and I found that the current network difficulty is stored in the nBits variable. – Nikos – 2016-10-25T11:42:41.650
So now I have to figure out how I can convert the nBits to Target. – Nikos – 2016-10-25T11:43:44.240