I haven't read any papers trying to analyze the amount of unspent outputs. More often, people are interested in the distribution of address' balances. This could be interesting because it reflects how evenly distributed bitcoin is.
I did find this article: http://www.coindesk.com/what-block-chain-analysis-tells-bitcoin/, which seems like it might be of interest to you and is related to the distribution of UTXOs.
If you call gettxoutsetinfo with the Bitcoin Core RPC calls, it tells some basic info about the UTXO set. I just did this and got:
{
"height" : 338396,
"bestblock" : "000000000000000009f32437cb28d54ff600ec020778c8ce84ecf93b99d5218c",
"transactions" : 4525842,
"txouts" : 16217914,
"bytes_serialized" : 566046691,
"hash_serialized" : "1ad2172e4d37ce21291c116580f5b527e4c302b9c2ce4e88a91c0c00f748fb8d",
"total_amount" : 13709764.78496462
}
So it seems that the average amount of an UTXO is:
13709764.78496462 / 16217914 = 0.84534699
To analyze the amount of outputs (note, this is not only UTXOs), I wrote up this quick script:
<?php
require_once 'jsonRPCClient.php';
$bitcoin = new jsonRPCClient('http://{username}:{password}@127.0.0.1:8332/');
$info = $bitcoin->getinfo();
$height = $info['blocks'];
$numTrials = 1000;
$includeCoinbase = false;
$cutoffs = array();
for ($i = 0; $i < 10; $i++) { $cutoffs[] = $i; }
for ($i = 1; $i < 10; $i++) { $cutoffs[] = 10*$i; }
for ($i = 1; $i < 10; $i++) { $cutoffs[] = 100*$i; }
for ($i = 1; $i < 10; $i++) { $cutoffs[] = 1000*$i; }
function GetRange($value)
{
global $cutoffs;
for ($i = 0; $i < count($cutoffs)-1; $i++)
{
if ($cutoffs[$i] <= $value && $value < $cutoffs[$i+1])
return $cutoffs[$i] . " - " . $cutoffs[$i+1];
}
return $cutoffs[count($cutoffs)-1] . " - ...";
}
$sum = 0;
$distribution = array();
for ($i = 0; $i < $numTrials; $i++)
{
$blockhash = $bitcoin->getblockhash(rand(1, $height));
$block = $bitcoin->getblock($blockhash);
$randTxIndex = rand(0, count($block['tx'])-1);
if ($randTxIndex == 0 && !$includeCoinbase) {
$i--;
continue;
}
$randTxHash = $block['tx'][$randTxIndex];
$randTx = $bitcoin->getrawtransaction($randTxHash, 1);
$numOutputs = count($randTx['vout']);
$randOutput = $randTx['vout'][rand(0, $numOutputs-1)];
$value = $randOutput['value'];
$sum += $value;
$distribution[GetRange($value)] += 1;
}
echo (json_encode($distribution, JSON_PRETTY_PRINT) . "\n");
echo "average: " . ($sum / $numTrials) . "\n";
And the results are (after being cleaned up a little):
average: 89.55518291596
START END COUNT
0 1 636
1 2 73
2 3 18
3 4 20
4 5 14
5 6 11
6 7 8
7 8 8
8 9 11
9 10 12
10 20 36
20 30 26
30 40 15
40 50 16
50 60 29
60 70 5
70 80 5
80 90 4
90 100 3
100 200 29
200 300 4
300 400 4
400 500 1
500 600 1
600 700 1
700 800 1
800 900 3
900 1000 0
1000 2000 2
2000 3000 1
3000 4000 0
4000 5000 0
5000 6000 1
6000 7000 0
7000 8000 0
8000 9000 0
9000 ... 2
Which, when plotted, gives:

And since the 0-1 outputs make the rest go out of scale, this is a plot without the smallest outputs:

1All of those questions would be answerable from the block chain. I would plot it as a histogram with x being the value of the UTXOs and y being the number of them. – Tyler – 2014-10-03T12:55:45.217
There's multiple properties related to UTXO that come to my mind (e.g. index number, amount, script, txid, age...) - distribution of what quantity do you mean? Try to be more specific please. – Jozef – 2014-10-19T12:41:08.420
@JozefKnaperek: Thanks, I was too much in the topic to realize that you could read it in so many different ways. I hope it is clearer now. – Murch – 2014-10-19T13:06:53.727
@Tyler: Yeah, I am aware of that. However, my question was, whether I have to do that work, or if someone else already has. – Murch – 2014-10-19T13:07:34.070
1
OK, makes sense to me now. But I haven't seen such analysis so far; I've found some nice online charts, but none of them does seem to be exactly what you're looking for. You can contact them though and they might add it (i.e. do the work for you :-)). Otherwise I guess you're on your own.
– Jozef – 2014-10-19T14:09:15.977UTXO's are stored in the Chainstate. Something like Levelhud to make navigating it better.
– KJ O – 2014-10-19T22:44:31.013